Problem packetResearch packetR1818
The fixed-alphabet determinization question remains open
Link to a section
The record cites sources for its explanation.
Recorded status: reported
Recorded scope: 2NFA-to-2DFA state complexity over each fixed finite input alphabet
Complete recorded scope and conditions
{
"kind": "family",
"statement": "2NFA-to-2DFA state complexity over each fixed finite input alphabet",
"family": "all finite input alphabets fixed independently of the source state count"
}Originating problem: Polynomial determinization of two-way finite automata
Authored record and scope
- Authored title
- The fixed-alphabet determinization question remains open
- Record type
- claim
- Stored status
- reported
- Evidence grade
- sourced
- Recorded scope data
- { "kind": "family", "statement": "2NFA-to-2DFA state complexity over each fixed finite input alphabet", "family": "all finite input alphabets fixed independently of the source state count" }
2Authored explanation
Sakoda and Sipser asked how many states are needed to replace nondeterminism by determinism when two-way head motion remains available. The canonical target fixes the input alphabet and asks whether the cost is polynomial in the number of source states.
Guillon, Prigioniero, and Taheri describe the general determinization question as open in their STACS 2026 paper. They record an exponential upper bound obtained by eliminating two-way motion and passing to a one-way DFA. Their polynomial construction uses a stronger target device, a 1-limited automaton with a common-guess annotation, so it does not give a 2DFA.
Chrobak's Theorems 6.2 and 6.3 give a tight quadratic tradeoff for unary 1NFAs versus 2DFAs. This already supplies a fixed-alphabet quadratic lower bound for the one-way source subclass. Adeogun and Kapoutsis's arXiv v2, revised 2026-07-06, proves the explicit lower bound \(h(h+1)/4\) for every 2DFA solving one-way liveness of height \(h\), whose source language has an \(h\)-state 1NFA. The fixed-binary transfer recorded in this packet preserves that quadratic order and gives an explicit liveness-based binary family. These bounds remain within a polynomial cost and leave the canonical question unanswered.
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3Evidence
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Verification source: doi.org ↗, Guillon, Prigioniero, and Taheri, STACS 2026, Introduction, pp. 48:2-48:3. The separate July 2026 lower bound appears in metadata.references.
4What was measured
5How it connects
Replaces
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Machine-readable record
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"title": "The fixed-alphabet determinization question remains open",
"summary": "The checked primary literature through 2026-07-28 still presents polynomial 2NFA-to-2DFA determinization as open. General conversion through a one-way DFA gives an exponential upper bound. Tight unary and recent one-way-liveness results give quadratic lower bounds.",
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"body": "Sakoda and Sipser asked how many states are needed to replace nondeterminism by determinism when two-way head motion remains available. The canonical target fixes the input alphabet and asks whether the cost is polynomial in the number of source states.\n\nGuillon, Prigioniero, and Taheri describe the general determinization question as open in their STACS 2026 paper. They record an exponential upper bound obtained by eliminating two-way motion and passing to a one-way DFA. Their polynomial construction uses a stronger target device, a 1-limited automaton with a common-guess annotation, so it does not give a 2DFA.\n\nChrobak's Theorems 6.2 and 6.3 give a tight quadratic tradeoff for unary 1NFAs versus 2DFAs. This already supplies a fixed-alphabet quadratic lower bound for the one-way source subclass. Adeogun and Kapoutsis's arXiv v2, revised 2026-07-06, proves the explicit lower bound \\(h(h+1)/4\\) for every 2DFA solving one-way liveness of height \\(h\\), whose source language has an \\(h\\)-state 1NFA. The fixed-binary transfer recorded in this packet preserves that quadratic order and gives an explicit liveness-based binary family. These bounds remain within a polynomial cost and leave the canonical question unanswered.",
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}7Provenance
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