Problem packetResearch packetR516
The literal graph is a four-vertex star at p=2 and has no vertices at p=3
Link to a section
The record reports a computation within its stated scope.
Recorded status: supported
Recorded scope: the literal coefficient-one graph at the two primes p=2 and p=3
Complete recorded scope and conditions
{
"kind": "bounded",
"statement": "the literal coefficient-one graph at the two primes p=2 and p=3",
"bounds": {
"p": {
"min": 2,
"max": 3
}
},
"exhaustive": true
}Originating problem: Prime exceptions to connectivity of the Markoff graph
Recorded relationships: Connectivity is proved below one million and beyond an explicit threshold
Authored record and scope
- Authored title
- The literal graph is a four-vertex star at p=2 and has no vertices at p=3
- Record type
- claim
- Stored status
- supported
- Evidence grade
- computational
- Recorded scope data
- { "kind": "bounded", "statement": "the literal coefficient-one graph at the two primes p=2 and p=3", "bounds": { "p": { "min": 2, "max": 3 } }, "exhaustive": true }
- Linked research record IDs
- R514
2Authored explanation
At \(p=2\), the vertices are \[ (1,1,1),\ (0,1,1),\ (1,0,1),\ (1,1,0). \] The three Vieta moves send \((1,1,1)\) to the other three vertices. Each leaf has two self-loop incidences, so the underlying graph is a connected star.
At \(p=3\), a solution with one zero coordinate would require two squares to sum to zero. Nonzero squares equal 1 in \(\mathbb F_3\), which forces the origin in this case. If all three coordinates are nonzero, the left side equals \(1+1+1=0\), while \(xyz=\pm1\). Hence the nonorigin solution set is empty. The coefficient-three equation has eight nonorigin solutions at the same prime, so the usual scaling changes the graph in characteristic 3.
The phrase “ordinary graph connectivity” does not settle whether the null graph counts as connected. The acceptance condition asks for two components whenever an exception exists, a certificate that cannot exist for an empty vertex set. A clean statement can declare the null graph connected for this problem, or quantify the main conjecture over \(p\geq5\) after listing the two small characteristics.
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Replay material: source only
3Evidence
A verification source is cited. This record has no executable replay attached.
Verification source: Elementary characteristic-2 and characteristic-3 argument, independently replayed by both packet artifacts
4What was measured
P3
Statement integrity finding
5How it connects
Supports
- claim
Evidenced by
- artifact
Informed by
- attempt
Recorded for
- problem
Cite this record
Cite the original sources separately.
Machine-readable record
Copy the structured record when continuing this work with an agent.
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"title": "The literal graph is a four-vertex star at p=2 and has no vertices at p=3",
"summary": "The p=2 graph is connected. The p=3 vertex set is empty, which exposes a null-graph convention absent from the current acceptance conditions.",
"relevance": "For Prime exceptions to connectivity of the Markoff graph, record mgpc-claim-small-characteristics (“The literal graph is a four-vertex star at p=2 and has no vertices at p=3”) records a bound, answer, status fact, or structural consequence. The record states: The p=2 graph is connected.",
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}7Provenance
View source, identifiers, and projection details
A statement this project treats as settled at the recorded evidence grade, with the work that backs it.