Problem packetResearch packetR77
Non-apwenian does not mean that a determinant vanishes
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Recorded status: established
Recorded scope: the parity pattern of all Baum-Sweet Hankel determinants
Complete recorded scope and conditions
{
"kind": "universal",
"statement": "the parity pattern of all Baum-Sweet Hankel determinants"
}Originating problem: Nonvanishing of Baum-Sweet Hankel determinants
Authored record and scope
- Authored title
- Non-apwenian does not mean that a determinant vanishes
- Record type
- claim
- Stored status
- established
- Evidence grade
- sourced
- Recorded scope data
- { "kind": "universal", "statement": "the parity pattern of all Baum-Sweet Hankel determinants" }
2Authored explanation
An apwenian binary sequence has every normalized Hankel determinant odd. Guo and Han's Example 11 classifies Baum-Sweet as non-apwenian. This agrees with \(H_3=-2\), but it leaves integer nonvanishing open. The classical function-field continued fraction also concerns a different object. Neither result resolves the candidate's claim.
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3Evidence
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Verification source: irma.math.unistra.fr ↗, Yining Guo and Guo-Niu Han, On a family of automatic apwenian sequences, Discrete Mathematics 348 (2025), Example 11
4How it connects
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"title": "Non-apwenian does not mean that a determinant vanishes",
"summary": "Exact integer elimination certifies \\(H_n\\ne0\\) for \\(1\\le n\\le110\\), and a self-reported audit modulo \\(100000007\\) finds nonzero residues through \\(n=4999\\); integer nonvanishing for every \\(n\\ge5000\\) remains open.",
"relevance": "For Nonvanishing of Baum-Sweet Hankel determinants, record bsh-claim-non-apwenian-distinction (“Non-apwenian does not mean that a determinant vanishes”) records a bound, answer, status fact, or structural consequence. The record states: Exact integer elimination certifies \\(H_n\\ne0\\) for \\(1\\le n\\le110\\), and a self-reported audit modulo \\(100000007\\) finds nonzero residues through \\(n=4999\\); integer nonvanishing for every \\(n\\ge5000\\) remains open.",
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"body": "An apwenian binary sequence has every normalized Hankel determinant odd. Guo and Han's Example 11 classifies Baum-Sweet as non-apwenian. This agrees with \\(H_3=-2\\), but it leaves integer nonvanishing open. The classical function-field continued fraction also concerns a different object. Neither result resolves the candidate's claim.",
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}6Provenance
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