Problem packetResearch packetR706
MacWilliams's product formula gives every rank count
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Recorded status: established
Recorded scope: all integers n >= 0 and 0 <= r <= n for symmetric n by n matrices over F_2 with unrestricted diagonal
Complete recorded scope and conditions
{
"kind": "universal",
"statement": "all integers n >= 0 and 0 <= r <= n for symmetric n by n matrices over F_2 with unrestricted diagonal"
}Originating problem: Rank log-concavity for symmetric binary matrices through order fifty
Recorded relationships: The symmetric binary rank distribution is strictly log-concave
Authored record and scope
- Authored title
- MacWilliams's product formula gives every rank count
- Record type
- claim
- Stored status
- established
- Evidence grade
- sourced
- Recorded scope data
- { "kind": "universal", "statement": "all integers n >= 0 and 0 <= r <= n for symmetric n by n matrices over F_2 with unrestricted diagonal" }
- Linked research record IDs
- R707
2Authored explanation
MacWilliams's Theorem 2 counts symmetric matrices of each rank over a finite field. Lewis, Liu, Morales, Panova, Sam, and Zhang reproduce it as Equation (4.5), using \(\operatorname{sym}(n,r)\) for symmetric matrices with no diagonal restriction. At \(q=2\), the result is \[ R_{n,r}= \left(\prod_{i=1}^{\lfloor r/2\rfloor}\frac{2^{2i}}{2^{2i}-1}\right) \left(\prod_{i=0}^{r-1}(2^{n-i}-1)\right), \] with empty products equal to one. This formula supplies every exact rank vector through order 50. The executable artifact evaluates all 1,325 entries as integers, checks that each row sums to \(2^{n(n+1)/2}\), and records an unambiguous SHA-256 digest of the complete coefficient stream.
The diagonal convention was checked in two ways. The later paper explicitly distinguishes \(\operatorname{sym}(n,r)\), with unrestricted diagonal, from \(\operatorname{sym}_0(n,r)\), whose diagonal is zero. Independent enumeration of all \(2^{n(n+1)/2}\) upper-triangular bit assignments for every \(1\leq n\leq6\) agrees with the product formula. The first six rows are \[ \begin{aligned} &(1,1),\\ &(1,3,4),\\ &(1,7,28,28),\\ &(1,15,140,420,448),\\ &(1,31,620,4340,13888,13888),\\ &(1,63,2604,39060,291648,874944,888832). \end{aligned} \]
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3Evidence
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Verification source: doi.org ↗, F. Jessie MacWilliams, Orthogonal Matrices Over Finite Fields, American Mathematical Monthly 76(2) (1969), 152-164, Theorem 2; Joel Brewster Lewis et al., Matrices with Restricted Entries and q-Analogues of Permutations, Journal of Combinatorics 2(3) (2011), 355-395, Equation (4.5) and the definitions preceding Proposition 4.12, arXiv:1011.4539
4How it connects
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"title": "MacWilliams's product formula gives every rank count",
"summary": "The unrestricted-diagonal formula specializes cleanly to characteristic two and reproduces the candidate's enumerated rows.",
"relevance": "For Rank log-concavity for symmetric binary matrices through order fifty, record sbmrlc-claim-macwilliams-rank-formula (“MacWilliams's product formula gives every rank count”) records a bound, answer, status fact, or structural consequence. The record states: The unrestricted-diagonal formula specializes cleanly to characteristic two and reproduces the candidate's enumerated rows.",
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"body": "MacWilliams's Theorem 2 counts symmetric matrices of each rank over a finite field. Lewis, Liu, Morales, Panova, Sam, and Zhang reproduce it as Equation (4.5), using \\(\\operatorname{sym}(n,r)\\) for symmetric matrices with no diagonal restriction. At \\(q=2\\), the result is\n\\[\nR_{n,r}=\n\\left(\\prod_{i=1}^{\\lfloor r/2\\rfloor}\\frac{2^{2i}}{2^{2i}-1}\\right)\n\\left(\\prod_{i=0}^{r-1}(2^{n-i}-1)\\right),\n\\]\nwith empty products equal to one. This formula supplies every exact rank vector through order 50. The executable artifact evaluates all 1,325 entries as integers, checks that each row sums to \\(2^{n(n+1)/2}\\), and records an unambiguous SHA-256 digest of the complete coefficient stream.\n\nThe diagonal convention was checked in two ways. The later paper explicitly distinguishes \\(\\operatorname{sym}(n,r)\\), with unrestricted diagonal, from \\(\\operatorname{sym}_0(n,r)\\), whose diagonal is zero. Independent enumeration of all \\(2^{n(n+1)/2}\\) upper-triangular bit assignments for every \\(1\\leq n\\leq6\\) agrees with the product formula. The first six rows are\n\\[\n\\begin{aligned}\n&(1,1),\\\\\n&(1,3,4),\\\\\n&(1,7,28,28),\\\\\n&(1,15,140,420,448),\\\\\n&(1,31,620,4340,13888,13888),\\\\\n&(1,63,2604,39060,291648,874944,888832).\n\\end{aligned}\n\\]",
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