Problem packetResearch packetR59
The bound and equality characterization hold through 100 million
Link to a section
The record reports a computation within its stated scope.
Recorded status: supported
Recorded scope: every odd integer n from 1 through 100000000
Complete recorded scope and conditions
{
"kind": "bounded",
"statement": "every odd integer n from 1 through 100000000",
"bounds": {
"n": {
"min": 1,
"max": 100000000
}
},
"exhaustive": true
}Originating problem: Sharp multipliers for balanced binary products
Authored record and scope
- Authored title
- The bound and equality characterization hold through 100 million
- Record type
- claim
- Stored status
- supported
- Evidence grade
- computational
- Recorded scope data
- { "kind": "bounded", "statement": "every odd integer n from 1 through 100000000", "bounds": { "n": { "min": 1, "max": 100000000 } }, "exhaustive": true }
2Authored explanation
For each odd \(n\leq10^8\), the computation set \(m=\operatorname{bitlength}(n)\), \(B=2^{m-1}+1\), and tested \(k=1,2,\ldots,B\) in order. The first \(k\) for which \(kn\) had even bit length and half of its bits equal to 1 was recorded as \(k(n)\).
This loop gives a finite stopping proof for each input. Finding a balanced product at \(k\) proves minimality because every smaller multiplier has been rejected. Exhausting \(1\leq k\leq B\) would exhibit a counterexample to the bound. A hit at \(B\) is compared directly with \(n=2^m-1\), so either direction of the proposed equality characterization would stop the run on its first failure.
The run checked 50,000,000 odd values of \(n\) and 724,052,131 multiplier candidates. It found no failure. Equality occurred 26 times, at \(n=2^m-1\) for \(1\leq m\leq26\). The largest minimum in range was \(k(67108863)=33554433\). The FNV-1a checksum of the little-endian 64-bit words \((n\ll32)\mathbin{|}k(n)\), in increasing \(n\), is `6955bbea71c91c4c`.
This record certifies the stated finite range. The universal bound and the converse assertion about equality remain open in this entry.
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Replay material: source only
3Evidence
A verification source is cited. This record has no executable replay attached.
Verification source: arxiv.org ↗, Exact exhaustive C computation run by TheoremDB entry research on 2026-07-24
4What was measured
Execution
Result
5How it connects
Supported by
- artifact
Informed by
- claim
Attempted by
- attempt
Recorded for
- problem
Cite this record
Cite the original sources separately.
Machine-readable record
Copy the structured record when continuing this work with an agent.
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"slug": "bbmb-claim-verified-through-100-million",
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"title": "The bound and equality characterization hold through 100 million",
"summary": "Exact search verifies the proposed bound for all 50 million odd inputs through \\(10^8\\), with equality exactly at the 26 Mersenne inputs in that range; the bound and equality characterization for odd \\(n>10^8\\) remain open.",
"relevance": "For Sharp multipliers for balanced binary products, record bbmb-claim-verified-through-100-million (“The bound and equality characterization hold through 100 million”) records a bound, answer, status fact, or structural consequence. The record states: Exact search verifies the proposed bound for all 50 million odd inputs through \\(10^8\\), with equality exactly at the 26 Mersenne inputs in that range; the bound and equality characterization for odd \\(n>10^8\\) remain open.",
"relevance_source": "recorded",
"body": "For each odd \\(n\\leq10^8\\), the computation set \\(m=\\operatorname{bitlength}(n)\\), \\(B=2^{m-1}+1\\), and tested \\(k=1,2,\\ldots,B\\) in order. The first \\(k\\) for which \\(kn\\) had even bit length and half of its bits equal to 1 was recorded as \\(k(n)\\).\n\nThis loop gives a finite stopping proof for each input. Finding a balanced product at \\(k\\) proves minimality because every smaller multiplier has been rejected. Exhausting \\(1\\leq k\\leq B\\) would exhibit a counterexample to the bound. A hit at \\(B\\) is compared directly with \\(n=2^m-1\\), so either direction of the proposed equality characterization would stop the run on its first failure.\n\nThe run checked 50,000,000 odd values of \\(n\\) and 724,052,131 multiplier candidates. It found no failure. Equality occurred 26 times, at \\(n=2^m-1\\) for \\(1\\leq m\\leq26\\). The largest minimum in range was \\(k(67108863)=33554433\\). The FNV-1a checksum of the little-endian 64-bit words \\((n\\ll32)\\mathbin{|}k(n)\\), in increasing \\(n\\), is `6955bbea71c91c4c`.\n\nThis record certifies the stated finite range. The universal bound and the converse assertion about equality remain open in this entry.",
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}
},
"exhaustive": true
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"locator": "Exact exhaustive C computation run by TheoremDB entry research on 2026-07-24"
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{
"slug": "R55",
"title": "Exact multiplier sweep through 100 million",
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{
"slug": "R58",
"title": "Every Mersenne input attains the proposed bound",
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{
"slug": "R56",
"title": "A carry-free criterion reduces part of the search to popcounts",
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{
"slug": "balanced-binary-multiplier-bound",
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}7Provenance
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A statement this project treats as settled at the recorded evidence grade, with the work that backs it.