{
  "schema": "theoremdb-agent-record-v1",
  "ref": "R284",
  "content_hash": null,
  "slug": "fib-claim-ai-proof-report-context",
  "type": "claim",
  "title": "A complete AI-generated proof was reported",
  "summary": "The MathOverflow author previously reported receiving claimed AI proofs without publishing their text.",
  "relevance": "For fib problem determinant range; fib problem nonzero support, record fib-claim-ai-proof-report-context (“A complete AI-generated proof was reported”) records a bound, answer, status fact, or structural consequence. The record states: The MathOverflow author previously reported receiving claimed AI proofs without publishing their text.",
  "relevance_source": "recorded",
  "body": "This historical report remains separate from the recorded proof now preserved in fib-claim-total-unimodular-review-pending.",
  "status": "claimed_unverified",
  "evidence_grade": "self_reported",
  "scope": null,
  "reproduction": {
    "schema": "theoremdb-reproduction-v1",
    "readiness": "source_only",
    "kind": "claim",
    "citation": {
      "url": "https://mathoverflow.net/questions/513340/is-the-determinant-of-this-fibonacci-sum-indicator-matrix-always-1-0-or/513372",
      "locator": "answer lines 327-371"
    },
    "missing": [
      "source",
      "command",
      "runtime",
      "expected_output"
    ]
  },
  "formal_statement": null,
  "source": {
    "url": "https://mathoverflow.net/questions/513340/is-the-determinant-of-this-fibonacci-sum-indicator-matrix-always-1-0-or/513372",
    "locator": "answer lines 327-371"
  },
  "models": [],
  "relations": [
    {
      "slug": "R307",
      "title": "Every Fibonacci-sum matrix is totally unimodular",
      "object_type": "claim",
      "relation": "informs",
      "direction": "outgoing"
    },
    {
      "slug": "R285",
      "title": "A complete AI-generated proof was reported",
      "object_type": "claim",
      "relation": "supersedes",
      "direction": "outgoing",
      "metadata": {
        "reason": "This revision records the independent-review boundary explicitly."
      }
    }
  ]
}